Integrand size = 29, antiderivative size = 194 \[ \int \frac {\sec ^4(c+d x) \tan ^5(c+d x)}{a+a \sin (c+d x)} \, dx=\frac {3 \text {arctanh}(\sin (c+d x))}{256 a d}+\frac {\sec ^6(c+d x)}{6 a d}-\frac {\sec ^8(c+d x)}{4 a d}+\frac {\sec ^{10}(c+d x)}{10 a d}+\frac {3 \sec (c+d x) \tan (c+d x)}{256 a d}+\frac {\sec ^3(c+d x) \tan (c+d x)}{128 a d}-\frac {\sec ^5(c+d x) \tan (c+d x)}{32 a d}+\frac {\sec ^5(c+d x) \tan ^3(c+d x)}{16 a d}-\frac {\sec ^5(c+d x) \tan ^5(c+d x)}{10 a d} \]
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Time = 0.23 (sec) , antiderivative size = 194, normalized size of antiderivative = 1.00, number of steps used = 11, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.241, Rules used = {2914, 2686, 272, 45, 2691, 3853, 3855} \[ \int \frac {\sec ^4(c+d x) \tan ^5(c+d x)}{a+a \sin (c+d x)} \, dx=\frac {3 \text {arctanh}(\sin (c+d x))}{256 a d}+\frac {\sec ^{10}(c+d x)}{10 a d}-\frac {\sec ^8(c+d x)}{4 a d}+\frac {\sec ^6(c+d x)}{6 a d}-\frac {\tan ^5(c+d x) \sec ^5(c+d x)}{10 a d}+\frac {\tan ^3(c+d x) \sec ^5(c+d x)}{16 a d}-\frac {\tan (c+d x) \sec ^5(c+d x)}{32 a d}+\frac {\tan (c+d x) \sec ^3(c+d x)}{128 a d}+\frac {3 \tan (c+d x) \sec (c+d x)}{256 a d} \]
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Rule 45
Rule 272
Rule 2686
Rule 2691
Rule 2914
Rule 3853
Rule 3855
Rubi steps \begin{align*} \text {integral}& = \frac {\int \sec ^6(c+d x) \tan ^5(c+d x) \, dx}{a}-\frac {\int \sec ^5(c+d x) \tan ^6(c+d x) \, dx}{a} \\ & = -\frac {\sec ^5(c+d x) \tan ^5(c+d x)}{10 a d}+\frac {\int \sec ^5(c+d x) \tan ^4(c+d x) \, dx}{2 a}+\frac {\text {Subst}\left (\int x^5 \left (-1+x^2\right )^2 \, dx,x,\sec (c+d x)\right )}{a d} \\ & = \frac {\sec ^5(c+d x) \tan ^3(c+d x)}{16 a d}-\frac {\sec ^5(c+d x) \tan ^5(c+d x)}{10 a d}-\frac {3 \int \sec ^5(c+d x) \tan ^2(c+d x) \, dx}{16 a}+\frac {\text {Subst}\left (\int (-1+x)^2 x^2 \, dx,x,\sec ^2(c+d x)\right )}{2 a d} \\ & = -\frac {\sec ^5(c+d x) \tan (c+d x)}{32 a d}+\frac {\sec ^5(c+d x) \tan ^3(c+d x)}{16 a d}-\frac {\sec ^5(c+d x) \tan ^5(c+d x)}{10 a d}+\frac {\int \sec ^5(c+d x) \, dx}{32 a}+\frac {\text {Subst}\left (\int \left (x^2-2 x^3+x^4\right ) \, dx,x,\sec ^2(c+d x)\right )}{2 a d} \\ & = \frac {\sec ^6(c+d x)}{6 a d}-\frac {\sec ^8(c+d x)}{4 a d}+\frac {\sec ^{10}(c+d x)}{10 a d}+\frac {\sec ^3(c+d x) \tan (c+d x)}{128 a d}-\frac {\sec ^5(c+d x) \tan (c+d x)}{32 a d}+\frac {\sec ^5(c+d x) \tan ^3(c+d x)}{16 a d}-\frac {\sec ^5(c+d x) \tan ^5(c+d x)}{10 a d}+\frac {3 \int \sec ^3(c+d x) \, dx}{128 a} \\ & = \frac {\sec ^6(c+d x)}{6 a d}-\frac {\sec ^8(c+d x)}{4 a d}+\frac {\sec ^{10}(c+d x)}{10 a d}+\frac {3 \sec (c+d x) \tan (c+d x)}{256 a d}+\frac {\sec ^3(c+d x) \tan (c+d x)}{128 a d}-\frac {\sec ^5(c+d x) \tan (c+d x)}{32 a d}+\frac {\sec ^5(c+d x) \tan ^3(c+d x)}{16 a d}-\frac {\sec ^5(c+d x) \tan ^5(c+d x)}{10 a d}+\frac {3 \int \sec (c+d x) \, dx}{256 a} \\ & = \frac {3 \text {arctanh}(\sin (c+d x))}{256 a d}+\frac {\sec ^6(c+d x)}{6 a d}-\frac {\sec ^8(c+d x)}{4 a d}+\frac {\sec ^{10}(c+d x)}{10 a d}+\frac {3 \sec (c+d x) \tan (c+d x)}{256 a d}+\frac {\sec ^3(c+d x) \tan (c+d x)}{128 a d}-\frac {\sec ^5(c+d x) \tan (c+d x)}{32 a d}+\frac {\sec ^5(c+d x) \tan ^3(c+d x)}{16 a d}-\frac {\sec ^5(c+d x) \tan ^5(c+d x)}{10 a d} \\ \end{align*}
Time = 3.63 (sec) , antiderivative size = 116, normalized size of antiderivative = 0.60 \[ \int \frac {\sec ^4(c+d x) \tan ^5(c+d x)}{a+a \sin (c+d x)} \, dx=\frac {90 \text {arctanh}(\sin (c+d x))+\frac {30}{(-1+\sin (c+d x))^4}+\frac {80}{(-1+\sin (c+d x))^3}+\frac {15}{(-1+\sin (c+d x))^2}-\frac {90}{-1+\sin (c+d x)}+\frac {48}{(1+\sin (c+d x))^5}-\frac {150}{(1+\sin (c+d x))^4}+\frac {100}{(1+\sin (c+d x))^3}+\frac {75}{(1+\sin (c+d x))^2}}{7680 a d} \]
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Time = 1.73 (sec) , antiderivative size = 127, normalized size of antiderivative = 0.65
method | result | size |
derivativedivides | \(\frac {\frac {1}{256 \left (\sin \left (d x +c \right )-1\right )^{4}}+\frac {1}{96 \left (\sin \left (d x +c \right )-1\right )^{3}}+\frac {1}{512 \left (\sin \left (d x +c \right )-1\right )^{2}}-\frac {3}{256 \left (\sin \left (d x +c \right )-1\right )}-\frac {3 \ln \left (\sin \left (d x +c \right )-1\right )}{512}+\frac {1}{160 \left (1+\sin \left (d x +c \right )\right )^{5}}-\frac {5}{256 \left (1+\sin \left (d x +c \right )\right )^{4}}+\frac {5}{384 \left (1+\sin \left (d x +c \right )\right )^{3}}+\frac {5}{512 \left (1+\sin \left (d x +c \right )\right )^{2}}+\frac {3 \ln \left (1+\sin \left (d x +c \right )\right )}{512}}{d a}\) | \(127\) |
default | \(\frac {\frac {1}{256 \left (\sin \left (d x +c \right )-1\right )^{4}}+\frac {1}{96 \left (\sin \left (d x +c \right )-1\right )^{3}}+\frac {1}{512 \left (\sin \left (d x +c \right )-1\right )^{2}}-\frac {3}{256 \left (\sin \left (d x +c \right )-1\right )}-\frac {3 \ln \left (\sin \left (d x +c \right )-1\right )}{512}+\frac {1}{160 \left (1+\sin \left (d x +c \right )\right )^{5}}-\frac {5}{256 \left (1+\sin \left (d x +c \right )\right )^{4}}+\frac {5}{384 \left (1+\sin \left (d x +c \right )\right )^{3}}+\frac {5}{512 \left (1+\sin \left (d x +c \right )\right )^{2}}+\frac {3 \ln \left (1+\sin \left (d x +c \right )\right )}{512}}{d a}\) | \(127\) |
risch | \(-\frac {i \left (-11484 \,{\mathrm e}^{5 i \left (d x +c \right )}+300 \,{\mathrm e}^{15 i \left (d x +c \right )}-11484 \,{\mathrm e}^{13 i \left (d x +c \right )}+23252 \,{\mathrm e}^{11 i \left (d x +c \right )}-40610 \,{\mathrm e}^{9 i \left (d x +c \right )}+690 i {\mathrm e}^{14 i \left (d x +c \right )}+90 i {\mathrm e}^{16 i \left (d x +c \right )}+45 \,{\mathrm e}^{i \left (d x +c \right )}+45 \,{\mathrm e}^{17 i \left (d x +c \right )}-3746 i {\mathrm e}^{8 i \left (d x +c \right )}+1798 i {\mathrm e}^{6 i \left (d x +c \right )}-1798 i {\mathrm e}^{12 i \left (d x +c \right )}+3746 i {\mathrm e}^{10 i \left (d x +c \right )}-690 i {\mathrm e}^{4 i \left (d x +c \right )}-90 i {\mathrm e}^{2 i \left (d x +c \right )}+300 \,{\mathrm e}^{3 i \left (d x +c \right )}+23252 \,{\mathrm e}^{7 i \left (d x +c \right )}\right )}{1920 \left ({\mathrm e}^{i \left (d x +c \right )}+i\right )^{10} \left ({\mathrm e}^{i \left (d x +c \right )}-i\right )^{8} d a}-\frac {3 \ln \left ({\mathrm e}^{i \left (d x +c \right )}-i\right )}{256 d a}+\frac {3 \ln \left ({\mathrm e}^{i \left (d x +c \right )}+i\right )}{256 a d}\) | \(277\) |
parallelrisch | \(\frac {\left (-45 \cos \left (10 d x +10 c \right )-9450 \cos \left (2 d x +2 c \right )-5400 \cos \left (4 d x +4 c \right )-2025 \cos \left (6 d x +6 c \right )-450 \cos \left (8 d x +8 c \right )-5670\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )+\left (45 \cos \left (10 d x +10 c \right )+9450 \cos \left (2 d x +2 c \right )+5400 \cos \left (4 d x +4 c \right )+2025 \cos \left (6 d x +6 c \right )+450 \cos \left (8 d x +8 c \right )+5670\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )+62280 \sin \left (3 d x +3 c \right )-20808 \sin \left (5 d x +5 c \right )+870 \sin \left (7 d x +7 c \right )+90 \sin \left (9 d x +9 c \right )-64 \cos \left (10 d x +10 c \right )-95360 \cos \left (2 d x +2 c \right )+33280 \cos \left (4 d x +4 c \right )-2880 \cos \left (6 d x +6 c \right )-640 \cos \left (8 d x +8 c \right )-112740 \sin \left (d x +c \right )+65664}{3840 a d \left (\cos \left (10 d x +10 c \right )+10 \cos \left (8 d x +8 c \right )+45 \cos \left (6 d x +6 c \right )+120 \cos \left (4 d x +4 c \right )+210 \cos \left (2 d x +2 c \right )+126\right )}\) | \(315\) |
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Time = 0.29 (sec) , antiderivative size = 187, normalized size of antiderivative = 0.96 \[ \int \frac {\sec ^4(c+d x) \tan ^5(c+d x)}{a+a \sin (c+d x)} \, dx=-\frac {90 \, \cos \left (d x + c\right )^{8} - 30 \, \cos \left (d x + c\right )^{6} - 1548 \, \cos \left (d x + c\right )^{4} + 2224 \, \cos \left (d x + c\right )^{2} - 45 \, {\left (\cos \left (d x + c\right )^{8} \sin \left (d x + c\right ) + \cos \left (d x + c\right )^{8}\right )} \log \left (\sin \left (d x + c\right ) + 1\right ) + 45 \, {\left (\cos \left (d x + c\right )^{8} \sin \left (d x + c\right ) + \cos \left (d x + c\right )^{8}\right )} \log \left (-\sin \left (d x + c\right ) + 1\right ) - 2 \, {\left (45 \, \cos \left (d x + c\right )^{6} + 30 \, \cos \left (d x + c\right )^{4} - 104 \, \cos \left (d x + c\right )^{2} + 48\right )} \sin \left (d x + c\right ) - 864}{7680 \, {\left (a d \cos \left (d x + c\right )^{8} \sin \left (d x + c\right ) + a d \cos \left (d x + c\right )^{8}\right )}} \]
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Timed out. \[ \int \frac {\sec ^4(c+d x) \tan ^5(c+d x)}{a+a \sin (c+d x)} \, dx=\text {Timed out} \]
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Time = 0.22 (sec) , antiderivative size = 214, normalized size of antiderivative = 1.10 \[ \int \frac {\sec ^4(c+d x) \tan ^5(c+d x)}{a+a \sin (c+d x)} \, dx=-\frac {\frac {2 \, {\left (45 \, \sin \left (d x + c\right )^{8} + 45 \, \sin \left (d x + c\right )^{7} - 165 \, \sin \left (d x + c\right )^{6} - 165 \, \sin \left (d x + c\right )^{5} - 549 \, \sin \left (d x + c\right )^{4} + 91 \, \sin \left (d x + c\right )^{3} + 301 \, \sin \left (d x + c\right )^{2} - 19 \, \sin \left (d x + c\right ) - 64\right )}}{a \sin \left (d x + c\right )^{9} + a \sin \left (d x + c\right )^{8} - 4 \, a \sin \left (d x + c\right )^{7} - 4 \, a \sin \left (d x + c\right )^{6} + 6 \, a \sin \left (d x + c\right )^{5} + 6 \, a \sin \left (d x + c\right )^{4} - 4 \, a \sin \left (d x + c\right )^{3} - 4 \, a \sin \left (d x + c\right )^{2} + a \sin \left (d x + c\right ) + a} - \frac {45 \, \log \left (\sin \left (d x + c\right ) + 1\right )}{a} + \frac {45 \, \log \left (\sin \left (d x + c\right ) - 1\right )}{a}}{7680 \, d} \]
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Time = 0.43 (sec) , antiderivative size = 156, normalized size of antiderivative = 0.80 \[ \int \frac {\sec ^4(c+d x) \tan ^5(c+d x)}{a+a \sin (c+d x)} \, dx=\frac {\frac {180 \, \log \left ({\left | \sin \left (d x + c\right ) + 1 \right |}\right )}{a} - \frac {180 \, \log \left ({\left | \sin \left (d x + c\right ) - 1 \right |}\right )}{a} + \frac {5 \, {\left (75 \, \sin \left (d x + c\right )^{4} - 372 \, \sin \left (d x + c\right )^{3} + 678 \, \sin \left (d x + c\right )^{2} - 476 \, \sin \left (d x + c\right ) + 119\right )}}{a {\left (\sin \left (d x + c\right ) - 1\right )}^{4}} - \frac {411 \, \sin \left (d x + c\right )^{5} + 2055 \, \sin \left (d x + c\right )^{4} + 3810 \, \sin \left (d x + c\right )^{3} + 2810 \, \sin \left (d x + c\right )^{2} + 955 \, \sin \left (d x + c\right ) + 119}{a {\left (\sin \left (d x + c\right ) + 1\right )}^{5}}}{30720 \, d} \]
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Time = 19.02 (sec) , antiderivative size = 496, normalized size of antiderivative = 2.56 \[ \int \frac {\sec ^4(c+d x) \tan ^5(c+d x)}{a+a \sin (c+d x)} \, dx=\frac {3\,\mathrm {atanh}\left (\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\right )}{128\,a\,d}+\frac {-\frac {3\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{17}}{128}-\frac {3\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{16}}{64}+\frac {5\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{15}}{32}+\frac {23\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{14}}{64}-\frac {67\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{13}}{160}+\frac {9091\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{12}}{960}+\frac {1717\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{11}}{480}+\frac {18257\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{10}}{960}-\frac {35\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^9}{192}+\frac {18257\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^8}{960}+\frac {1717\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^7}{480}+\frac {9091\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6}{960}-\frac {67\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5}{160}+\frac {23\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4}{64}+\frac {5\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3}{32}-\frac {3\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2}{64}-\frac {3\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}{128}}{d\,\left (a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{18}+2\,a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{17}-7\,a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{16}-16\,a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{15}+20\,a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{14}+56\,a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{13}-28\,a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{12}-112\,a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{11}+14\,a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{10}+140\,a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^9+14\,a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^8-112\,a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^7-28\,a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6+56\,a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5+20\,a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4-16\,a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3-7\,a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+2\,a\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )+a\right )} \]
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